Math, asked by RiderBoy90, 3 months ago

If a number of n-digits is a perfect square and ‘n’ is an odd number, then which of the following is the number of digits of its square root?

Answers

Answered by vivekbt42kvboy

12

Step-by-step explanation:

no of digits in a perfect square is n

If n is odd then no of digits in its square roots is

2

n+1

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