Question

If a number of two digits is k times of the sum of its
digits, when the digits of number are reversed, then
how many times will it be the sum of its digits?​

Answer 1

Step-by-step explanation:

Let the two digit number be 10x+y. Hence, the number obtained on interchanging the digits is 10y+x. Also, sum of digits is x+y.

So, we get,

10x+y=K(x+y)   -(1)

10y+x=N(x+y)   -(2)

Adding (1) and (2) we get,

11(x+y)=(N+K)(x+y)

Therefore, N+K=11

N=11-K.

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