If a number selected at random from the number 6, 7, . . . . . . . ,50, then find the probability of getting a prime
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3
Answer:
S={6,7,8,9,10,11,12,13,14,15,16,17,18 19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50}
n(S)=45
Let event A be of getting a prime number A={7,11,13,17,19,23,29,31,37,41,43,47}
n(A)=12
(P)A=n(A)/n(S)
=12/45
=4/15
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Answered by
1
Answer:
Ans. 4/15
Step-by-step explanation:
Here,
Prime no.s between 6 and 50 = 12 numbers
So , p(getting prime no.)= 12/45 = 4/15
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