Question

if a number that is divisible by 3, has 8 in its unit place, then what can be possible digits in tens place

Answer 1

so if a number has to be divisible by 3 the sum of the numbers should be the multiple of 3....

so, if 8 is in the ones place...the numbers in tens place could be...

1 , since 1+8 = 9

4 , since 4+8 = 12

7 , since 7+8 = 15...

so the answer is 1,4 and 7...

HOPE U UNDERSTAND..! :D