Question

if a number x is choosen as random from the -5,-4,-3,-2,-1,0,1,2,3,4,5 .what is the probability that x^3>-2​

Answer 1

$|\Omega|=11$

$x^3>-2\\x>\sqrt[3]{-2}(\approx-1,3)$

Therefore

$A=\{-1,0,1,2,3,4,5\}\\|A|=7\\\\P(A)=\dfrac{7}{11}$