if a number x is choosen at random from the numbers-3,-2,-1,0,1,2,3 . what is the probability that
Answers
Answer:
We will check square of each number given above, that whose value comes ≤ 4
⠀
- (- 3)² = (- 3 × - 3) = 9⠀
- (- 2)² = (- 2 × - 2) = 4⠀
- (- 1)² = (- 1 × - 1) = 1⠀
- ( 0 )² = (0 × 0) = 0⠀
- ( 1 )² = (1 × 1) = 1⠀
- ( 2 )² = (2 × 2) = 4⠀
- ( 3 )² = (3 × 3) = 9⠀
⠀
We seen that Square of - 2, - 1 , 0, 1, 2 are either equal to or less than 4.
⠀
FACTS :
• Probability of any event falls b/w 0 and 1
• 0 indicates uncertainty of event, while 1 indicates certainty of event
• 0 ≤ P(E) ≤ 1
• P(E) + P(not E) = 1
Answer:
We will check square of each number given above, that whose value comes ≤ 4
⠀
(- 3)² = (- 3 × - 3) = 9⠀
(- 2)² = (- 2 × - 2) = 4⠀
(- 1)² = (- 1 × - 1) = 1⠀
( 0 )² = (0 × 0) = 0⠀
( 1 )² = (1 × 1) = 1⠀
( 2 )² = (2 × 2) = 4⠀
( 3 )² = (3 × 3) = 9⠀
⠀
We seen that Square of - 2, - 1 , 0, 1, 2 are either equal to or less than 4.
\underline{\bigstar\:\textsf{According to the given Question :}}
★According to the given Question :
\begin{gathered}:\implies\sf P(E)=\dfrac{Number\:of\:events}{Total\:number\:of\:events}\\\\\\:\implies\sf P(E) = \dfrac{5}{7}\\\\\\:\implies\sf P(E) = 0.71\end{gathered}
:⟹P(E)=
Totalnumberofevents
Numberofevents
:⟹P(E)=
7
5
:⟹P(E)=0.71
⠀
\therefore\:\underline{\textsf{Hence, probability of getting x$^\text2 \leqslant $ 4 is \textbf{0.71}}}.∴
Hence, probability of getting x
2
⩽ 4 is 0.71
.
\rule{200}{1}
FACTS :
• Probability of any event falls b/w 0 and 1
• 0 indicates uncertainty of event, while 1 indicates certainty of event
• 0 ≤ P(E) ≤ 1
• P(E) + P(not E) = 1
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