If a numerator of a fraction is incraesed by 1 its become 3/4 if the denominator is increased by 2 its value become 1/2 find the fraction.
plz solve it tomorrow is my prelims
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let assume X is numerator
and let assume Y is denominator
and fraction will become like this numerator/denominator
fraction=a
a=X/Y
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Y+X=3/4
==>X+Y=3/4
4X+4Y=3 --->A)
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X+2Y=1/2
2X+4Y=1 -->B)
subtract equation A and equation B
we WILL GET
4X+4Y=3
2X+4 =1
2x =2
2x=2
x=2/2
x=1
put x=1 in eq A
we will get
2*(1)+4Y=1
2+4Y=1
4Y=1-2
4Y=-1
Y=-1/2
fraction we know that x/y so that
1/-1/4
x//y=-4/1
NabilAhmed:
but the answer should be 5/8
and let assume Y is denominator
and fraction will become like this numerator/denominator
fraction=a
X+1/Y=3/4
4X+4=3Y
4X-3Y=-4 A
X/(Y+2)=1/2
2X=Y+2
2X-Y=2B
Now multiply equation A with 2 and B with 4
8X-6Y=-8 C
8X-4Y=8 D
Subtract equation D from C,
-2Y=-16
Y=8
Put Y=8 in equation D)
8X-4(8)=8
8X-32=8
8X=40
X=5
Denominator y=8
X/Y=5/8
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