Question

if a our c worked 12 day, a our c worked 20 days, and a our b worked 15 days, If they all start working together, how many days will they complete?​

Answer 1

Answer:

c+b in one day = 1/12 days

a+c in one day - 1/20 days

b+c in one day - 1/15 days

a+b+b+c+c+a= 1/20+ 1/12+1/15

LCM = 60

2(a+b+c)= (3+5+4)/60

2(a+ b+c)=12/60=1/5

a+b+c=1/5*2

a+b+c=1/10

a+b+c=10 days