Question

if a,p are the zeroes of the polynomial=2y^+y+5,find the value of a+p-ap=?​

Answer 1

Answer:

-3

Step-by-step explanation:

sum of zeroes = - b/ a (- coefficient of y / coefficient of y^2) or a+p

product of zeroes = c/a (coefficient of constant/ coefficient of y^2) or ap

hence sum of zeroes is -1/2 and product of zeroes is 5/2

that is a+ p is -1/2 ap is 5/2

Given a+p-ap = -1/2 - 5/2

= -(1/2 + 5/2)

= -(6/2)

= -3

therefore answer is -3

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Answer 2

$\sf\huge\underline{Question:}$

If a,p are the zeroes of the polynomial 2y^2+y+5, find the value of a+p-ap=?

$\sf\huge\underline{Answer:}$

Given, zeroes of the polynomial are a and p

→ sum of zeroes

$a + p = \frac{ -coefficient \: of \: y}{coefficient \: of \: {y}^{2} }$

$= \frac{ - 1}{2}$

→ product of zeroes

$a \times p = \frac{coefficient \: of \: constant}{coefficient \: of \: {y}^{2} }$

$= \frac{5}{2}$

→ required result

$a + p - ap = \frac{ - 1}{2} - \frac{5}{2}$

$= \frac{ - 6}{2} = - 3$

Therefore, the answer required is -3

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