Question

if a pair of complementary angles are in the ratio 3:7 then find bigger angle.​

Answer 1

$\mathfrak{{\pmb{{\underline{Given}}:}}}$

• A pair of complementary angles are in the ratio $\sf{\pmb{3:7}}$

$\mathfrak{{\pmb{{\underline{To~find}}:}}}$

• The larger angle

$\mathfrak{{\pmb{{\underline{Solution}}:}}}$

• We know that complementary angles are 90°
• Let the ratios of the angles be 3x and 7x
• 7x is the larger angle

$\sf\implies{3x+7x=90 \degree }$

$\sf\implies{10x=90\degree}$

$\sf\implies{x={\dfrac{90}{10}}}$

$\sf{~~~~~~~ {\blue{•~{\underline{\boxed{\sf{\pmb{x=9}}}}}}}}$

$\therefore\mathfrak{{\pmb{{\underline{Required~answer}}:}}}$

• Larger angle = 7x = 7 × 9 = $\sf{\underline{\underline{\pmb{~63 \degree~}}}}$

Answer 2

Answer:

Given:-

• Ratio of the pair of complementary angle is 3:7

To Find:-

• The bigger angle

Solution:-

Let angles be 3x and 7x

We know that sum of two complementary angle is equal to 90°

=> 3x + 7x = 90°

=> 10x = 90°

=> x = 90/10

=> x = 9

3 × 9 = 27

7 × 9 = 63

Hence bigger angle is 7x i.e. 63°

HOPE IT HELPS

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