Math, asked by Manasjain5703, 11 months ago

If a pair of dice is thrown.Find the probability that the sum of digits is neither 7 nor 11

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Answered by shrutisru
26

Probablity of sum being 7 = 6/36 = 1/6


Probablity of sum being 11 = 2/36 =1/18


Probablity of sum neither 7 nor 11 = 1 -( probability of sum being 7 or 11)


= 1 - (2/9) = 7/9


Therefore Probablity of sum neither 7 nor 11 is 7/9.

Answered by shrutica24
0

Answer:

7/9

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