If a pair of dice is thrown.Find the probability that the sum of digits is neither 7 nor 11
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Probablity of sum being 7 = 6/36 = 1/6
Probablity of sum being 11 = 2/36 =1/18
Probablity of sum neither 7 nor 11 = 1 -( probability of sum being 7 or 11)
= 1 - (2/9) = 7/9
Therefore Probablity of sum neither 7 nor 11 is 7/9.
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7/9
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