Question

if a pair of dice is tossed simultaneously and the numbers on the upper face are added then what will be the probability of not getting a sum 4 or 8

Answer 1

Answer:

the probability is 7/9

Step-by-step explanation:

there are 36 outcomes out of these only these does not sum to 4 or 8:

(1,3)(2,2)(2,6)(3,1)(3,5)(4,4)(5,3)(6,2)

hence 36-8=28outcomes

p(not getting sum 4 or 8)=28/36

=7/9