If a pair of opposite sides are equal of a cyclic quadrilateral , Prove the diagonals are also equal
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Proof Clearly
BD = BD (common)
CBD = ADB (alternate angle)
BDC = ABD (alternate angle)
So Δ ADB ≈ Δ CDB
Similarly Δ ADC ≈ Δ CBA
So Diagonals are equal.. :)
BD = BD (common)
CBD = ADB (alternate angle)
BDC = ABD (alternate angle)
So Δ ADB ≈ Δ CDB
Similarly Δ ADC ≈ Δ CBA
So Diagonals are equal.. :)
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