if a pair of tangents to a circle which are inclined to each other at an angle of 60° then find the degree measure of angle poq
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PA and PB are tangents drawn from an external point P to the circle.
∠OAP = ∠OBP = 90° (Radius is perpendicular to the tangent at point of contact)
In quadrilateral OAPB,
∠APB + ∠OAD + ∠AOD + ∠OBP = 360°
∴ 100° + 90° + ∠AOB + 90° = 360°
⇒ 280° + ∠AOB = 360°
⇒ ∠AOB = 360° – 280° = 80°
Thus, the angle between the two radius, OA and OB is 80°.
I take my best in answer ☺☺☺
PA and PB are tangents drawn from an external point P to the circle.
∠OAP = ∠OBP = 90° (Radius is perpendicular to the tangent at point of contact)
In quadrilateral OAPB,
∠APB + ∠OAD + ∠AOD + ∠OBP = 360°
∴ 100° + 90° + ∠AOB + 90° = 360°
⇒ 280° + ∠AOB = 360°
⇒ ∠AOB = 360° – 280° = 80°
Thus, the angle between the two radius, OA and OB is 80°.
I take my best in answer ☺☺☺
aryavyas77avav:
thanx
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