Question

 If a parabola is represented by x²+ 2 x + 1 then its zeros are​

Answer 1

Answer:

x square+2x+1=0........

Answer 2

Answer:

Zeroes are : (x-1) and (x-1)

x = 1

Step-by-step explanation:

On splitting the middle term we get,

$x^2+2x+1=0\\\\x^2+x+x+1=0\\\\x(x+1)+1(x+1)=0\\\\(x+1)(x+1)=0$

therefore zeroes are (x-1) and (x-1),

so x = 1

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