If a parallel line is cut by transversal then each pair of co-interior angles so formed are supplementary.prove it
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TPT: <BEF + <EFD=180°
<AEF + <BEF=180° -(i)
<EFC + <EFD=180° -(ii)
Adding eq. (i) and (ii)
<AEF + <BEF + <EFC + <EFD=180°+180°
2<BEF + 2<EFD= 360°
{<AEF=<EFD (alt. <s) and <BEF=<EFC (alt. <s)}
2(<BEF + <EFD)=360°
<BEF + <EFD= 360°/2
=180°
PROVED
<AEF + <BEF=180° -(i)
<EFC + <EFD=180° -(ii)
Adding eq. (i) and (ii)
<AEF + <BEF + <EFC + <EFD=180°+180°
2<BEF + 2<EFD= 360°
{<AEF=<EFD (alt. <s) and <BEF=<EFC (alt. <s)}
2(<BEF + <EFD)=360°
<BEF + <EFD= 360°/2
=180°
PROVED
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