Question

if a parallellogram side a be 56 cm and 3 m long how much area and perimeter that the shape covered (give ans in sq.m sq.cm​

Answer 1

Answer:

Area and Perimeter of the Rectangle are explained below:

Length is denoted by l, width (breadth) is denoted by w(b) and diagonal is denoted by d. There are two lengths, two widths and two diagonals.

area & perimeter of the rectangle

Formulas for Area and Perimeter of the Rectangle are given below :

• Perimeter of the rectangle = 2(l + w) units

• Length of Rectangle = p/2 - w units

• Width(w) of Rectangle = p/2 - l units

• Diagonal of Rectangle = √(l 2 + w 2 ) units

• Area of Rectangle = l x w sq.units

• Length of Rectangle = A/w units

• Width of Rectangle = A/l units

Some solved examples on Area and Perimeter of the Rectangle

1) Find the perimeter of a rectangle whose length and width are 25 m and 15 m respectively.

Solution :

Length = l = 25 m and Width = w = 15 m

∴ P = 2 ( l + w )

⇒ = 2 ( 25 + 15 )

⇒ = 2 x 40

⇒ = 80 m

Perimeter = 80 m

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2)How many rectangles can be drawn with 36 cm as the perimeter, given that the sides are positive integers in cm ?

Solution :

Perimeter = 36

⇒ 2 ( l + w ) = 36

⇒ l + w = 18

Since length and width are positive integers in centimeters. Therefore, possible dimensions are :

( 1, 17 )cm , ( 2, 16 ) cm , ( 3, 15 ) cm, (4 , 14) cm, ( 5,13) cm, ( 6, 12) cm , ( 7, 11) cm, ( 8, 10 ) cm, ( 9, 9) cm.

Hence, there are 9 rectangles.

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4) The length of a rectangular field is twice its width. A man jogged around it 5 times and covered a distance of 3 km. What is the length of the field?

Solution :

In completing one round of the field distance covered is equal to the perimeter of the field.

∴ Distance covered in 5 rounds = 5 x Perimeter

= 5 x 2 ( l + w )

= 10 x ( l + w)

= 10 x ( 2w + w ) [ length = l = 2w ]

= 10 x 3w

= 30 w

But, the total distance covered is given = 3 km = 3000 m.

∴ 30 x w = 3000

⇒ w = 3000 / 30

⇒ w = 100 m

⇒ Length = 2 w = 2 x 100 = 200 m.

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