if a parallelogram is cyclic, then it is a rectangle. justify your answer.
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because in a cyclic parallelogram the opposite sides are equal that's why it is a rectangle
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Hello mate ☺
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Solution:
➡It is given that parallelogram ABCD is cyclic. We need to prove that ABCD is a rectangle.
∠B=∠D (Opposite angles of a parallelogram are equal) ....(1)
∠B+∠D=180° ...... (2)
(Sum of opposite angles of a cyclic quadrilateral is equal to 180°)
Using equation (1) in equation (2), we get
∠B+∠B=180°
⇒2∠B=180°
⇒∠B=180/2=90° …...(3)
➡Therefore, ABCD is a parallelogram with ∠B=90° which means that ABCD is a rectangle.
I hope, this will help you.☺
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