Question

If a parallelogram is cyclic,then prove that it is a rectangle​

Answer 1

Step-by-step explanation:

every parallelogram has opposite sides and angles are same so that it is a rectangle

Answer 2

Question :

If a parallelogram is cyclic,then prove that it is a rectangle.

Solution :

The ABCD is a cyclic parallelogram

Then ∠A = ∠C

( Opposite angle of parallelogram )

In Cyclic parallelogram ABCD

∠A + ∠C = 180°

( Sum of opposite angle of cyclic parallelogram = 180° )

→ 2∠A = 180°

$→ ∠A = \: \frac{180°}{2} = \: 90°$

and ∠B = ∠D

( Opposite angle of parallelogram )

In Cyclic parallelogram

∠B + ∠D = 180°

( Sum of opposite angle of cyclic parallelogram = 180° )

→ 2∠B = 180°

$∠B = \frac{180°}{2} = \: 90°$

So,in parallelogram ABCD all angle are right angle then ABCD is rectangle.