Question

if a particle changes its position as
x=sin^2t
find its
a) initital postion(x),velocity(v), acceleration (a)

b) add t=45degree in X,v and a

please give the solution of all not only one .
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Answer 1

x=sin^2t(initial position given)

v=dx/dt =2sint*cost=sin2t

a=d^2x/dt^2=2cos2t

at 45°

v=sin90°=1

a=0

position =1/2

Answer 2

Answer:

x=sin square t

a.) initial position (x)= Sin sq.t

b.) velocity (v)=dx /dt

v=dx/dt=2 Sin t cos t

c.) acc.=dv/dt.

dv/dt.=2(-sin t sint+cos t cos t)

acc=2(cos sq. T-sin sq. t)

B.) t=45 degree.

a.) x=1/root 2.

b.) v=1.

c) a=0.

Explanation:

hope it helps u..