if a particle covers 14 revolution in 11 seconds in a circle of radius 10cm find acceleration of the particle
Answers
Answered by
1
Answer:
Here T=
2
1
sec the required centripetal acceleration for moving in circle is
a
c
=
r
v
2
=
r
(rω)
2
=rω
2
=r×(2π/T)
2
So a
c
=0.25×(2π/0.5)
2
=16π
2
×0.25=4.0π
2
Similar questions