If a particle is displaced by distance to a plus 3J plus 5KM by applying a force five a plus 3J plus 3KN then calculate the work done by the force
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=3i^−5j^+4k^=(r2−r1)F=5i^−3j+2k^w=F.r=15+15+8=38JHence,optionAiscorrectanswer.
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If a particle is displaced by distance to a plus 3J plus 5KM by applying a force five a plus 3J plus 3KN then calculate the work done by the force
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