If a particle is moving on a straight line. Its displacement at time t is given by s(in m)=-4t^2+2t then its velocity and acceleration at time t=1/2 seconds are options:
A)-2m/s,-8m/s^2
B)2m/s,6m/s^2
C)-2m/s,8m/s^2
D)2m/s,8m/s^2
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From Newton’s second law of eqn.
S= 4t^2 + 2t
v= dS/dt
=8t+2
velocity at t=1/2s
=6m/s
a=dv/dt
=8 m/s^2
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nagamalleswarikother:
answer changes
You have written 4t^2 in it
if u don't have problem refer my attachment
What i don't Understand
u have not taken negative sign for solving ur answer
Ok i understand
I dont see that negative sign
thanks bro
even at first I to haven't observed it when there was no option I checked it
Ya
Answered by
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Explanation:
hey mate here is ur answer
please refer the attachment
any doubts can be clarified in comments
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