If a particle is projected at an angle of 45o, then find the relation between the range and the maximum height attained by the particle.
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Hello.... ☺
Maximum height, H = (u²sin²θ)/2g
Given the angle of projection is 45°,
∴ H= [u²(1/√2)²]/2g
= u²/4g
= 1/4 (u²/g)
Thank you ☺
Maximum height, H = (u²sin²θ)/2g
Given the angle of projection is 45°,
∴ H= [u²(1/√2)²]/2g
= u²/4g
= 1/4 (u²/g)
Thank you ☺
Answered by
4
heya....
your answer is in attachment ...✌ ✌
your answer is in attachment ...✌ ✌
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