Question

If a particle is projected from point p on the inclined plane. Speed of projection is u inclination angle of plane is 0 = 45° and the particle is projected perpendicularly to the surface. If the distance 'OP' is u2/√2g .Then find the angle at which the particle will hit the horizontal surface. (i.e. find the value of 5)​

Answer 1

Answer:

1 is the answer maths assessment and answer

Answer 2

Answer:

he horizontal distance covered by the projectile in time t  is ut

The vertical distance covered during that time is g t²/2

tanθ =  horizontal distance/ vertical distance

t= 2u tanθ/g

Horizontal distance = 2u²tanθ secθ/g

#SPJ3

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Explanation: