If a particle is projected horizontally with an initial speed u from a cliff of height h then find the horizontal distance covered by it when it reaches the ground.
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H=1/2gt²
t=√2h/g
Horizontal speed=u
Horizontal distance=speed × time=u√(2h/g)
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t=√2h/g
Horizontal speed=u
Horizontal distance=speed × time=u√(2h/g)
Pls mark as brainliest
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