If a particle is projected vertically
upward from ground at t= 0 and at two
instant t = 2s and t = 8s particle at
same height ‘h’. The value of height h
is ( g= 10 m/s2) :
1) h = 40 m 2) h = 80 m
3) h = 100 m 4) h = 160 m
Answers
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answer is h = 80 m
t1= 2sec
t2= 8 sec
t1×t2= 2h/g
2×8=2h/10
160= 2h
h= 80
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