Question

if a particle is projected with a velocity v then it's ratio of potential and kinetic energy is 2:1 then find the ratio of P.E. and K.E if it's velocity is doubled​

Answer 1

Explanation:

Example: We drop this 0.1 kg apple 1 m. What speed does it hit the ground with?

Velocity from KE: v = √( 2 × KE / m )

Put in formula for PE: v = √( 2 × mgh / m )

Cancel m/m: v = √( 2gh )