If a particle is projected with u = 30 i + 40 m/s. Find the time of flight for
projectile. Also find displacement at 6 second.
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Answer:
Time of flight =
g
2usinθ
=
10
2×80×sin30
o
=8
As particle during journey at t=2sec and at t=6sec will be at same height and hence vertical displacement is zero.
Horizontal displacement =(ucosθ)×(6−2)
=80×
2
3
×4
=160
3
m
∴ Average velocity =
4
160
3
=40
3
m/sec
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