Question

If a particle is projected with u = 30 i + 40 m/s. Find the time of flight for
projectile. Also find displacement at 6 second.​

Answer 1

Answer:

Time of flight =

g

2usinθ

=

10

2×80×sin30

o

=8

As particle during journey at t=2sec and at t=6sec will be at same height and hence vertical displacement is zero.

Horizontal displacement =(ucosθ)×(6−2)

=80×

2

3

×4

=160

3

m

∴ Average velocity =

4

160

3

=40

3

m/sec

solution

Explanation:

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Answer 2

Answer's in the pic...........