Physics, asked by bhavikrathod75, 4 months ago

If a particle is projectiled with same velocity at angle θand π/2 - θ then prove that the ranges of the particle in both the cases are same.

Answers

Answered by lahari60

0

Explanation:

R=u²sin2θ/g

for θ and π/2-θ

sin2θ value is same. so range is same.

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