Physics, asked by mona6395, 10 months ago

If a particle is thrown up with sone velocity more than 10 m/s then distance travelled by the particle in first second of its descent will be

Answers

Answered by sumanmohapatra2003
1

Answer:

Explanation:

time of ascent be t

0=10−gt

t=1s

s=ut−1/2gt²

= g/2

Answered by shabihulhasan671
0

Answer:

What the question Mate...

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