Question

if a particle move from origin to 30cm left of and then
50 cm right in 6 sec.
Then calculates its:
distance
displacement
speed
velocity​

Answer 1

Given :-

◉ Particles moves from origin to 30 cm left and 50 cm right in 6 second.

To Find :-

◉ Distance, Displacement, Speed, Velocity

Solution :-

We know, Distance is the actual path length, here the total path length travelled by the particle is:

⇒ 30 + 50

⇒ 80 cm

Similarly, Displacement is the shortest distance between the final and initial position. Let the direction of the particle on its left side be negative and on the right side be positive.

∴ Displacement = -30 + 50

⇒ Displacement = 20 cm

Also, Speed is the rate of change of distance per unit time. Here, the distance travelled by the particle is 80 cm and the time taken is 6 s

∴ Speed = 80/6

⇒ Speed = 13.33 cm/s

Now, The velocity is the rate of change of displacement per unit time, So displacement of the particle is 20 cm and time taken is 6 s

∴ Velocity = 20 / 6

⇒ Velocity = 3.33 cm/s

Hence, The particle has:

• Distance travelled = 80 cm
• Displacement made = 20 cm
• Speed = 13.33 cm/s
• Velocity = 3.33 cm/s