Question

If a particle moves along a circle with constant speed, then the ratio of its angular speed about any point on the circle to that of the centre is​

Answer 1

Answer:

Solution :

Let, O be a point on a circle and P be the position of the particle at any time T , such that

∠POA=θ . Then, ∠PCA=20

Here, C is the centre of the circle.

Angular velocity of P about O is ω0=dθdt

and angular velocity of P about C is,

ωc=ddt(2θ)=2dθdt

or ωc=2ω0

Proved...

Explanation:

hope you get it