Question

If a particle moves along a line by s=(6^2+1)m. Then the velocity when t=3 seconds is

Answer 1

Answer:

S=t

3

−6

2

+3t+4

v=

dt

ds

So =3t

2

−12+3=v

again differentiate ,a=

dt

dv

6t−12=0

t=2s

v=3(2)

2

−12×2+3=−9ms

−1