Question

If a particle moves with uniform acceleration
with rate of 8 m/s. After 10 second the velocity
of particle becomes 3 times its initial velocity.
Find the distance travelled by that particle in
11th sec.

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Answer 1

Answer:

We all know that

V= U+ AT

After ten seconds, V=3U.

Therefore,

3U = U + 8×10

2U = 80

U = 40.

Now, apply S nth formula.

S of 11= 40 + 1÷2×8(2×11-1)

S of 11= 40+ 4×21

Therefore distance travelled in 11 seconds is equal to 84 metres