Question

If a particle of charge -0.2mc where placed at a certain location with in an electric field the magnitude of the electric force it would feel is 1N .What is the magnitude of electric field at its location??? Ans: 5000N/C Solution plzzzzZz

Answer 1

Answer:

Using

F=qE

E=F/q

$= \frac{1}{0.2 \times {10}^{ - 3} } \\ = \frac{ {10}^{4} }{2} \\ = 5000 \:$

Hence, E=5000 N/C