Question

If a particle of mass 5 kg moves uniformly along a circle of radius 10 m at 10 m/s, then what is the work done by centripetal force during its one revolution?


a. 0.5 kNm
b. zero
c. infinity
d. none of the above

Answer 1

Given:-

Mass of particle (m) = 5kg

Radius of circle (r) = 10m

velocity of particle (v) = 10m/s

To Find:-

Centripetal force during one revolution .

Solution:-

As we know that the force acting towards the centre of Circle is called centripetal force.

⟹ F = mv²/r

here,

m is the mass of particle

v is the speed of particle

r is the radius of Circle

Put the value we get

⟹ F = 5×10²/10

⟹ F = 5×100/10

⟹ F = 500/10

⟹ F = 50N

∴ The centripetal force during 1 revolution is 50N.

Answer 2

Option(d) is the correct answer.

none of the above.

Given:

The mass of the particle uniformly along a circle is 5 kg. The radius of the circle is 10 m and the speed is 10m/s.

To find:

The centripetal force during the revolution.

Solution:

Mass of the object(m)= 5 Kg

The radius of the circle(r)= 10 I'm

The velocity of the particle(v)= 10m/s

We know, the centripetal force is

$f = m \frac{ {v}^{2} }{r}$

Put the values,

f= 5×10×10/10

f=50 N

So, the centripetal force during the revolution is 50 N.

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