Question

If a particle of mass M is divided into two particles of mass m and (M-m) at rest and acquires vortex velocities, then their de brawl wavelengths are (3) m: (M-m) (1) (M - m) : m (2) 1:1 (4) M: m​

Answer 1

 36 thanks please

By momentum conservation, Mv = m1v1 + m2v2 ...(1) As M is initially rest so v = 0 Now (1) becomes, 0 = m1v1 + m2v2 or m1v1 = - m2v2 , it means ...