If a particle of mass m is moving with constant
velocity v parallel to x-axis in x-y plane as shown in
fig. Its angular momentum with respect to origin at
(I =Px mü
any time t will be
y
m
V
b
X
0 (0,0)
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Answer:
The position vector is given as,
r=yj^
The velocity of the body is given as,
v=vi^
The angular momentum is given as,
L=m(r×v)
L=m(yj^×vi^)
L=−myvk^
Thus, the angular momentum with respect to origin is −myvk^.
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