Question

If a particle of mass M is tied to a light inextensible string fixed at point P and particle is projected at a with velocity VA=√4gL as shown.Find

i) velocity of Points B and C.

ii) tension in the string at B and C.

Assume Particle is projected in the vertical plane.​

Answer 1

$\huge\star{\mathfrak{\underline{\underline{\red{Answer}}}}}$

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${V}_{B}$ = $\sqrt {2gL}$ (from energy conservation);

${V}_{C}$=$\sqrt {6gL}$

$\implies$ ${T}_{B}$ +Mg= $\frac{M{v}^{2}_{B}}{L}$

${T}_{B}$= Mg

${T}_{C}$- Mg = $\frac{M{v}^{2}_{C}}{L}$

${T}_{C}$=$\large{\boxed{\boxed{7Mg}}}$ (where M $\implies$ Mass of Particle.

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Answer 2

Answer:

Check the attachment!!