Question

if a particle rotates with 20 rad/s angular velocity and 200 cm ls linear velocity then what is the perpandi cular distance of particule from the axis ? ​

Answer 1

$\huge{\textbf{\textsf{\pink{Answer\::}}}}$

We know that,

→ v = ω r

→ r = $\sf{\dfrac{v}{ω}}$

→ r = $\sf{\dfrac{2}{20}}$

→ r = $\sf\red{0.1~m}$

Answer 2

Given:

A particle rotates with 20 rad/s angular velocity and 200 cm/s is the linear velocity.

To find:

Perpendicular distance of particle from axis?

Calculation:

The general relation between angular velocity and linear velocity is :

$\therefore \: v = \omega \times r$

• Here 'r' is the perpendicular distance.

$\implies r = \dfrac{v}{ \omega}$

$\implies r = \dfrac{200/100}{20}$

$\implies r = \dfrac{2}{20}$

$\implies r = 0.1 \: m$

$\implies r = 10\: cm$

So, perpendicular distance from axis is 10 cm.