Question

if a particle start its motion from (1,2) point and moves with a velocity of (2i+3j)m/s.
Then what will be the x and y coordinates of the particle after 10 sec.
Please give the explanation thoroughly

Answer 1

Answer:

The magnitude of velocity after 10 seconds is

Explanation:

The particle moves with initial velocity and acceleration as given, the velocity is calculated using equation of motion

Given is the initial velocity u = 2 i + 3 j  

Acceleration a = 0.3 i + 0.2 j

Final velocity v =?

Time t = 10sec

From first equation of motion, we have –

v=u+a  t

v = u + at

v=(2 i+3 j)+(0.3 i+0.2 j) 10