Question

If a particle starting from rest has acceleration that increases lineraly with timeas a=2t then the distance travelled in third second will be
a)9m
b)8/3 m
c)19/3 m
d)11/4 m​

Answer 1

Answer:

Answer my latest question then I'll edit my answer

Answer 2

Answer:

given that

a=2t

now we know that  

\frac{dv}{dt} =a

dv=2t dt

\int\limits^v_0 {} \, dv= \int\limits^t_0 {2t} \, dt  

v= t^{2}  

now we know that  

\frac{ds}{dt} =vds= t^{2} dt

\int\limits^s_0 {} \, ds= \int\limits^t_0 { t^{2}}\, dt  

s= \frac{ t^{3} }{3}  

now in three seconds it will travel

S_{3} = \frac{ 3^{3} }{3}  

S_{3} = \frac{27}{3}  

in 2 seconds it will travel

S_{2}= \frac{8}{3}  

therefore in third second it will travel

S_{3rd}= S_{3} -S_{12}    

S_{3rd} = \frac{19}{3}  answer.............

Explanation:

19/3 is answer