Question

if a particle starting from rest is moving with a uniform accelaration of 10ms-2, then the final velocity when it covers a distance of 2km is

Answer 1

The total distance travelled is =625m The initial velocity is u=0ms^-1 The acceleration is a=10ms^-2 The time is t=5s

Answer 2

Explanation:

u=0 , a=10 , s=200m

2as = v^2 -u^2

2×10×200 = v^2 - 0

v^2 = 4000

v = 20m/s