If a particle starts from rest and moves with uniform acceleration "a" such that it travels distances sm and sn in the mth and nth seconds then "a" is equal to
A)sm-sn/(m-n)
B)sm+sn/(m-n)
C)sm-sn/(m+n)
D)sm+sn/(m+n
Answer is option (A)
Please explain the process
Answers
Answered by
2
Answer:
Explanation:hdekho accleratiom kya hota hai rate of change of velocity with time ab jo bhi distance cover ho rhi hai kuch velocity se hogi wose wos ques se maan lo aur kuch time me wose bhi dononko divide kro answer hai
Answered by
4
Answer:
Answer is option A.
Explanation:
We have,
Sm= u + a( m-1/2) eqn (1)
Sn= u + a (n-1/2) eqn(2)
Subtracting eqn(2) from (1)
Sm-Sn = u+ a( m-1/2) - u - a (n-1/2)
=> Sm-Sn = am - an
=> Sm-Sm/(m-n) = a
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