if a particle starts moving with acceleration of 2m/s.then what is the distance travelled by it in 5th half second
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heya buddy here is ur answer....
v=u+at
u(primary speed) =0
v=10m/s
dx=dv/dt
dx=10/5
dx=2m
then travelled distance is 2 met
if hlp mark as brainliest
v=u+at
u(primary speed) =0
v=10m/s
dx=dv/dt
dx=10/5
dx=2m
then travelled distance is 2 met
if hlp mark as brainliest
rutujapatole:
tysm
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