If a perfect cube is divided by 9, there are only 3 possible remainders. Give an example for each.
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Answer:
Remainders are 0 , 1 and 8
Step-by-step explanation:
2³ (8) divided by 9 has remainder 8
5³ (125) divided by 9 has remainder 8
3³ ( 27 ) divided by 9 has remainder 0
7³ ( 343) divided by 9 has remainder 1
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