Question

IF A PERIMETER OF A RECTANGLE IS 450 m square and the length is twice is breadth then find the length breadth and area of the same rectangle.​

Answer 1

Answer:

Let the length of the rectangle be ‘l’. Let the breadth of the rectangle be ‘b’.

Let the perimeter be ‘P’.

P = 2(l+b)

When P= 60 metre, l = 2b. So,

60 = 2(2b+b)

60 = 2(3b)

60 = 6b

b = 10 metre

To find length, use the equation l=2b.

l = 2*10 = 20 metre

Area of the rectangle = l*b square units.

Area = 20*10 = 200 square metre

Answer 2

$\huge\bold{Question}$

If the Perimeter of a rectangle is 450 square and the length is twice it's breath, then find the length, breadth and area of the same rectangle.

$\tt\underline{Given :-}$

Perimeter of rectangle = 450 m

Let us assume that Breadth = x

$\tt\underline{So,}$

Length = 2x

$\boxed{\purple{\bf{P\:=\:2(a\:+\:b)}}}$

$\tt\underline{So,}$

450 = 2(2x + x)

⟹ 450 = 2(3x)

⟹ 450 = 6x

⟹ x = 450/6

⟹ x = 75

Let us put the value of x

Length = 2x = 2(75) = 150 m

Breathe = x = 75

Now let us find the area,

$\boxed{\purple{\bf{A\:=\:l\:×\:b}}}$

Area = 150 × 75

= 11,250 m²

$\tt\underline{Required\: Answer :-}$

Length of the rectangle = 150 m

Breathe of the rectangle = 75 m

Area of the rectangle = 11,250 m²

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Hope it's helpful :)