If a perpendicular drawn from an obtuse-angeld vertex of a rhombus to the opposite side of bisect the side, find all angles of the rhombus
please solve this without using trigonometry. i am in 8th class and thus have not studied trigonometry yet. plz do not spam otherwise I'll report your answer for which your profile may be suspended.
if you solve this in time, 30 points will be given...
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1... Let the acute angle be A and obtuse angle be B. Rhombus ABCD, and angle A = angle C = acute angles. The perpendicular from B to AD be BE. Now in ÎABE, AE = ED = AB/2 = AD/2 cos A = AE/AB = 1/2 angle A = 600 = angle C angle B = angle D = (360 - 2x60)/2 = 1200.Read more on Sarthaks.com - https://www.sarthaks.com/10143/perpendicular-drawn-obtuse-angled-vertex-rhombus-opposite-bisects-find-angles-rhombus
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