Question

If a perpendicular drawn from an obtuse angled vertex of a rhombus to tge opposite side bisects the side , all the angles of the rhombus are...........................................

Answer 1

$\huge\underline\mathfrak\pink{Answer⤵}$

✏ 90°

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Answer 2

$\huge\bold\red{SolutiOn:}$

Let the acute angle be A and obtuse angle be B.

Rhombus ABCD, and angle A = angle C = acute angles.

The perpendicular from B to AD be BE.

Now in Î$\sf{ABE, AE = ED = \frac{AB}{2} = \frac{AD}{2}}$

$\sf{cos A = \frac{AE}{AB} = \frac{1}{2}}$ angle A = 600 = angle C  

angle B = angle D = $\sf{\frac{(360 - 2x60)}{2} = 1200.}$

"OR"

Refer to the attachment dear....